0=-16x^2+16x+450

Solution for 0=-16x^2+16x+450 equation:

0=-16x^2+16x+450

We move all terms to the left:

0-(-16x^2+16x+450)=0

We add all the numbers together, and all the variables

-(-16x^2+16x+450)=0

We get rid of parentheses

16x^2-16x-450=0

a = 16; b = -16; c = -450;
Δ = b2-4ac
Δ = -162-4·16·(-450)
Δ = 29056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{29056}=\sqrt{64*454}=\sqrt{64}*\sqrt{454}=8\sqrt{454}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{454}}{2*16}=\frac{16-8\sqrt{454}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{454}}{2*16}=\frac{16+8\sqrt{454}}{32}
$